Which point on Figure E5-1 best represents the impedance of a series circuit consisting of a 300-ohm resistor and a 19-picofarad capacitor at 21.200 MHz?
Why For a series RC circuit the impedance is Z = R - jXc, with Xc = 1/(2*pi*f*C). Here Xc = 1/(2*pi*21.2e6*19e-12) = about 395 ohms, so Z is approximately 300 - j395 ohms. On the rectangular graph that means going right 300 units on the resistance axis and down about 400 units on the reactance axis, which is where Point 1 falls.
Watch out The point at 300 + j400 is the mirror image above the real axis, which would be a 300-ohm resistor in series with an inductor, not a capacitor; other points swap the resistance and reactance values.
Capacitors go DOWN on the graph (negative j), inductors go UP. Read R across, X up or down.