Why A battery behaves like an ideal voltage source in series with its internal resistance, so terminal voltage = EMF minus I times R(internal). The smaller that internal resistance, the less the voltage sags and the less energy is wasted heating the cell when heavy current is drawn. That means a low-resistance cell can deliver large currents, which is why starting and high-power transmit applications call for them.
Watch out Rapid recharge is the closest trap, since charge current also passes through the internal resistance, but the pool credits the discharge side; internal resistance does not set cell voltage (chemistry does) or by itself determine service life.
Low internal R means low voltage sag under load, so it can dump big current.
Resistance is what holds current back, so low resistance lets more current out. Pick the answer with current in it.