What is the phase angle between the voltage across and the current through a series RLC circuit if XC is 500 ohms, R is 1 kilohm, and XL is 250 ohms?
Why In a series RLC circuit the reactances subtract: X = XL - XC = 250 - 500 = -250 ohms, so the net reactance is capacitive. The phase angle is arctan(X/R) = arctan(250/1000) = 14.0 degrees. Because the circuit is net capacitive, the current leads the voltage, which is the same as saying the voltage lags the current.
Watch out The 14.0 degrees with voltage leading choice has the right magnitude but the wrong sign; voltage leads only when XL is larger than XC (net inductive). The 68.2 degree answers come from flipping the ratio and taking arctan(1000/250).
ELI the ICE man: with C dominant (ICE), current leads. Angle = arctan(net X / R), here arctan(250/1000) = 14 degrees.